Sum of Factorials of the digits of N.

Sum of Factorial of the digits of the given number: Write a python program to compute sum of
the factorials of each digit of a given integer. Write a separate function for calculating the
factorial of a number.

def fact(n):
    result = 1
    for i in range(n):
        result *= i + 1
    return result

def sum_of_fact(n):
    result = 0
    if(n <= 0):
     return 1
    else:
     while n > 0:
         result += fact(n % 10)
         n = n // 10
     return result

print(sum_of_fact(int(input())))

import java.util.Scanner;

public class Solution {

 public static long factorialN(long n) {
  if (n <= 0)
   return 1;
  else 
   return n * factorialN(n-1);
 }

 public static void main(String[] args) {
  Scanner scan = new Scanner(System.in);
  long n = scan.nextLong();
  int sum = 0;
  if(n <= 0) {
   System.out.println("1");
  } else {
   while(n != 0) {
    sum = sum + (int)factorialN(n%10);
    n = n/10;
   }
   System.out.println(sum);
  }
 }
}

C
#include <stdio.h>

long long int factorialN(long long int n) {
 if (n <= 0)
  return 1;
 else 
  return n * factorialN(n-1); 
}

int main(int argc, char const *argv[]) {
 long long int n = 0;
 long long int sum = 0;
 scanf("%llu",&n);
 if(n <= 0) {
  printf("1");
 } else {
  while(n != 0) {
   sum = sum + factorialN(n%10);
   n = n/10;
  }
  printf("%llu\n",sum);
 }
 return 0;
}